A father said to his son, “Two years ago I was three times as old as you, but in fourteen years I shall be only twice as old as you.” What were the ages of each?
Scroll down for a clue and further down for the answer.
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Clue: The information in the first part of the equation can be expressed by the equation: f-2 = 3(s-2) where f= the father’s current age and s= the son’s current age.
Scroll down for the answer.
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Answer: The father is 50 and the son is 18. This means that two years ago, their ages were 48 and 16. In 14 year’s time, their ages will be 64 and 32.
If f= the father’s current age and s= the son’s current age, then the information in the first part the question can be represented in an equation:
f-2 = 3(s-2)
The information in the second part of the question can be represented in the following equation:
f + 14 = 2s + 28.
The second equation minus the first equation leaves us with s = 18 and f = 50.
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